Make input parameter of StronglyConnectedComponents as Out

Topics: algorithm
Jan 1, 2009 at 4:00 AM
I would prefer

IDictionary<int, int> com;
var comp = testGraph.StronglyConnectedComponents(out com);

instead of this currently,
var com = new Dictionary<int, int>();
 var comp = testGraph.StronglyConnectedComponents(com);

Similar to how ShortestPathsBellmanFord works
Jan 1, 2009 at 6:20 PM
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